ASVAB Math Knowledge Practice Test 873469 Results

Your Results Global Average
Questions 5 5
Correct 0 3.01
Score 0% 60%

Review

1

Which of the following statements about parallel lines with a transversal is not correct?

37% Answer Correctly

angles in the same position on different parallel lines are called corresponding angles

all acute angles equal each other

same-side interior angles are complementary and equal each other

all of the angles formed by a transversal are called interior angles


Solution

Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).


2

If a = c = 5, b = d = 9, and the blue angle = 53°, what is the area of this parallelogram?

66% Answer Correctly
20
5
45
32

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 5 x 9
a = 45


3

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

vertical, supplementary

supplementary, vertical

obtuse, acute

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


4

If the area of this square is 16, what is the length of one of the diagonals?

69% Answer Correctly
4\( \sqrt{2} \)
7\( \sqrt{2} \)
6\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)


5

If c = 8 and y = 2, what is the value of 9c(c - y)?

69% Answer Correctly
432
18
-216
-288

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

9c(c - y)
9(8)(8 - 2)
9(8)(6)
(72)(6)
432