| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
Which of the following statements about a triangle is not true?
area = ½bh |
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sum of interior angles = 180° |
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exterior angle = sum of two adjacent interior angles |
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perimeter = sum of side lengths |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Breaking apart a quadratic expression into a pair of binomials is called:
deconstructing |
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normalizing |
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factoring |
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squaring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
This diagram represents two parallel lines with a transversal. If y° = 159, what is the value of a°?
| 142 | |
| 168 | |
| 28 | |
| 21 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with y° = 159, the value of a° is 21.
What is 8a5 - 8a5?
| 64a10 | |
| 0a5 | |
| 64a5 | |
| 10 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a5 - 8a5 = 0a5
Solve -9b + b = 7b + 2y + 8 for b in terms of y.
| -\(\frac{1}{16}\)y - \(\frac{1}{2}\) | |
| -\(\frac{1}{2}\)y + 1 | |
| 2\(\frac{1}{3}\)y - \(\frac{1}{3}\) | |
| -1\(\frac{1}{4}\)y + \(\frac{1}{4}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-9b + y = 7b + 2y + 8
-9b = 7b + 2y + 8 - y
-9b - 7b = 2y + 8 - y
-16b = y + 8
b = \( \frac{y + 8}{-16} \)
b = \( \frac{y}{-16} \) + \( \frac{8}{-16} \)
b = -\(\frac{1}{16}\)y - \(\frac{1}{2}\)