When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + 6c = -6c + 3y + 3 for c in terms of y.
| 1\(\frac{3}{10}\)y + \(\frac{1}{5}\) | |
| \(\frac{3}{8}\)y + \(\frac{3}{4}\) | |
| -\(\frac{3}{7}\)y + \(\frac{3}{7}\) | |
| -3\(\frac{1}{3}\)y - 2\(\frac{1}{3}\) |