ASVAB Math Knowledge Practice Test 875495 Results

Your Results Global Average
Questions 5 5
Correct 0 3.74
Score 0% 75%

Review

1

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

4

5

3

2


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


2

A right angle measures:

90% Answer Correctly

180°

45°

90°

360°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


3

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

problem

expression

equation

formula


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

This diagram represents two parallel lines with a transversal. If a° = 16, what is the value of x°?

73% Answer Correctly
167
164
160
28

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with a° = 16, the value of x° is 164.


5

Solve for b:
2b + 5 < \( \frac{b}{3} \)

44% Answer Correctly
b < 1\(\frac{16}{19}\)
b < -3
b < -\(\frac{4}{33}\)
b < 3\(\frac{3}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

2b + 5 < \( \frac{b}{3} \)
3 x (2b + 5) < b
(3 x 2b) + (3 x 5) < b
6b + 15 < b
6b + 15 - b < 0
6b - b < -15
5b < -15
b < \( \frac{-15}{5} \)
b < -3