ASVAB Math Knowledge Practice Test 875968 Results

Your Results Global Average
Questions 5 5
Correct 0 3.11
Score 0% 62%

Review

1

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c - a

c2 + a2

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


2

If the base of this triangle is 6 and the height is 7, what is the area?

58% Answer Correctly
52\(\frac{1}{2}\)
56
21
15

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 6 x 7 = \( \frac{42}{2} \) = 21


3

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
6\( \sqrt{2} \)
5\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


4

The dimensions of this cylinder are height (h) = 8 and radius (r) = 8. What is the volume?

62% Answer Correctly
128π
36π
512π
96π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(82 x 8)
v = 512π


5

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

normalizing

deconstructing

factoring

squaring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.