When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 6c = -2c + 8z - 6 for c in terms of z.
| -2\(\frac{2}{3}\)z - 3 | |
| z + \(\frac{2}{3}\) | |
| 2\(\frac{4}{5}\)z - 1\(\frac{1}{5}\) | |
| 1\(\frac{1}{2}\)z + \(\frac{5}{6}\) |