When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 2c = 8c + 5y + 3 for c in terms of y.
| \(\frac{1}{7}\)y + \(\frac{4}{7}\) | |
| -\(\frac{3}{4}\)y - \(\frac{3}{4}\) | |
| 3y + 3\(\frac{1}{2}\) | |
| -2y + 4 |