| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.42 |
| Score | 0% | 48% |
Which of the following statements about a parallelogram is not true?
a parallelogram is a quadrilateral |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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opposite sides and adjacent angles are equal |
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the area of a parallelogram is base x height |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Solve -3c - 3c = -7c - 8y - 2 for c in terms of y.
| -9y + 2 | |
| -1\(\frac{5}{6}\)y + 1\(\frac{1}{6}\) | |
| -\(\frac{8}{13}\)y + \(\frac{1}{13}\) | |
| -1\(\frac{1}{4}\)y - \(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-3c - 3y = -7c - 8y - 2
-3c = -7c - 8y - 2 + 3y
-3c + 7c = -8y - 2 + 3y
4c = -5y - 2
c = \( \frac{-5y - 2}{4} \)
c = \( \frac{-5y}{4} \) + \( \frac{-2}{4} \)
c = -1\(\frac{1}{4}\)y - \(\frac{1}{2}\)
Solve for y:
7y + 2 > \( \frac{y}{-2} \)
| y > 2\(\frac{1}{2}\) | |
| y > -5 | |
| y > -\(\frac{4}{15}\) | |
| y > 2\(\frac{9}{20}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
7y + 2 > \( \frac{y}{-2} \)
-2 x (7y + 2) > y
(-2 x 7y) + (-2 x 2) > y
-14y - 4 > y
-14y - 4 - y > 0
-14y - y > 4
-15y > 4
y > \( \frac{4}{-15} \)
y > -\(\frac{4}{15}\)
Simplify (3a)(4ab) + (6a2)(3b).
| 30a2b | |
| 6ab2 | |
| 30ab2 | |
| -6a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(3a)(4ab) + (6a2)(3b)
(3 x 4)(a x a x b) + (6 x 3)(a2 x b)
(12)(a1+1 x b) + (18)(a2b)
12a2b + 18a2b
30a2b
Solve for b:
3b + 4 = \( \frac{b}{5} \)
| 1\(\frac{7}{11}\) | |
| -1\(\frac{3}{7}\) | |
| -\(\frac{7}{29}\) | |
| \(\frac{6}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
3b + 4 = \( \frac{b}{5} \)
5 x (3b + 4) = b
(5 x 3b) + (5 x 4) = b
15b + 20 = b
15b + 20 - b = 0
15b - b = -20
14b = -20
b = \( \frac{-20}{14} \)
b = -1\(\frac{3}{7}\)