When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2b - 4b = b - 6z + 2 for b in terms of z.
| 1\(\frac{1}{5}\)z + 1\(\frac{2}{5}\) | |
| \(\frac{2}{3}\)z - \(\frac{2}{3}\) | |
| -\(\frac{3}{5}\)z - \(\frac{9}{10}\) | |
| z + 3 |