When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 4c = 6c + 5y - 2 for c in terms of y.
| -1\(\frac{1}{4}\)y - 2 | |
| -2\(\frac{1}{4}\)y + \(\frac{1}{2}\) | |
| \(\frac{1}{4}\)y + \(\frac{1}{4}\) | |
| 14y + 7 |