When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 6c = 8c - 3z - 4 for c in terms of z.
| -\(\frac{3}{16}\)z + \(\frac{1}{4}\) | |
| 1\(\frac{1}{6}\)z + \(\frac{2}{3}\) | |
| 1\(\frac{3}{8}\)z + \(\frac{1}{4}\) | |
| \(\frac{1}{2}\)z + \(\frac{3}{8}\) |