ASVAB Math Knowledge Practice Test 885302 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

Solve for y:
y2 - 7y - 11 = -y + 5

48% Answer Correctly
2 or -3
-2 or 8
7 or -7
3 or -8

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 - 7y - 11 = -y + 5
y2 - 7y - 11 - 5 = -y
y2 - 7y + y - 16 = 0
y2 - 6y - 16 = 0

Next, factor the quadratic equation:

y2 - 6y - 16 = 0
(y + 2)(y - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 2) or (y - 8) must equal zero:

If (y + 2) = 0, y must equal -2
If (y - 8) = 0, y must equal 8

So the solution is that y = -2 or 8


2

If side a = 9, side b = 5, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{106} \)
\( \sqrt{74} \)
\( \sqrt{68} \)
5

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 92 + 52
c2 = 81 + 25
c2 = 106
c = \( \sqrt{106} \)


3

The dimensions of this trapezoid are a = 5, b = 5, c = 7, d = 7, and h = 4. What is the area?

50% Answer Correctly
18
24
32\(\frac{1}{2}\)
26

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(5 + 7)(4)
a = ½(12)(4)
a = ½(48) = \( \frac{48}{2} \)
a = 24


4

Which of the following expressions contains exactly two terms?

81% Answer Correctly

quadratic

polynomial

monomial

binomial


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


5

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

bisects

intersects

midpoints

trisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.