When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 6c = 4c + 9z + 5 for c in terms of z.
| -4\(\frac{1}{2}\)z + 1 | |
| -1\(\frac{3}{4}\)z + \(\frac{3}{8}\) | |
| -\(\frac{1}{5}\)z - \(\frac{4}{5}\) | |
| 3z + 5 |