When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve b - 6b = 4b + 5z + 8 for b in terms of z.
| -3\(\frac{2}{3}\)z - 2\(\frac{2}{3}\) | |
| 1\(\frac{5}{14}\)z + \(\frac{1}{2}\) | |
| \(\frac{7}{8}\)z - 1\(\frac{1}{8}\) | |
| 1\(\frac{3}{7}\)z + 1\(\frac{2}{7}\) |