| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
Solve for x:
x - 8 > \( \frac{x}{-5} \)
| x > 3\(\frac{3}{7}\) | |
| x > 6\(\frac{2}{3}\) | |
| x > -1\(\frac{31}{41}\) | |
| x > -1\(\frac{5}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
x - 8 > \( \frac{x}{-5} \)
-5 x (x - 8) > x
(-5 x x) + (-5 x -8) > x
-5x + 40 > x
-5x + 40 - x > 0
-5x - x > -40
-6x > -40
x > \( \frac{-40}{-6} \)
x > 6\(\frac{2}{3}\)
Solve 9c - 9c = -2c - 6x + 7 for c in terms of x.
| \(\frac{2}{3}\)x + 1\(\frac{1}{3}\) | |
| \(\frac{3}{11}\)x + \(\frac{7}{11}\) | |
| 1\(\frac{1}{7}\)x - \(\frac{2}{7}\) | |
| -1\(\frac{2}{3}\)x - \(\frac{7}{9}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
9c - 9x = -2c - 6x + 7
9c = -2c - 6x + 7 + 9x
9c + 2c = -6x + 7 + 9x
11c = 3x + 7
c = \( \frac{3x + 7}{11} \)
c = \( \frac{3x}{11} \) + \( \frac{7}{11} \)
c = \(\frac{3}{11}\)x + \(\frac{7}{11}\)
If BD = 22 and AD = 27, AB = ?
| 11 | |
| 3 | |
| 7 | |
| 5 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDSolve for a:
-5a - 2 = 9 + 7a
| -\(\frac{11}{12}\) | |
| 2\(\frac{1}{3}\) | |
| 1\(\frac{1}{2}\) | |
| 4\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-5a - 2 = 9 + 7a
-5a = 9 + 7a + 2
-5a - 7a = 9 + 2
-12a = 11
a = \( \frac{11}{-12} \)
a = -\(\frac{11}{12}\)
If the base of this triangle is 1 and the height is 7, what is the area?
| 3\(\frac{1}{2}\) | |
| 60 | |
| 75 | |
| 66 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 1 x 7 = \( \frac{7}{2} \) = 3\(\frac{1}{2}\)