When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 5c = c - 4y + 3 for c in terms of y.
| \(\frac{1}{4}\)y + \(\frac{3}{4}\) | |
| -1\(\frac{1}{3}\)y + \(\frac{5}{9}\) | |
| \(\frac{2}{15}\)y - \(\frac{2}{15}\) | |
| -1\(\frac{1}{5}\)y - 1 |