ASVAB Math Knowledge Practice Test 890250 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

Find the value of b:
-3b + y = 3
3b - 9y = 6

42% Answer Correctly
-1\(\frac{3}{8}\)
-1\(\frac{14}{41}\)
-1\(\frac{3}{4}\)
6\(\frac{1}{2}\)

Solution

You need to find the value of b so solve the first equation in terms of y:

-3b + y = 3
y = 3 + 3b

then substitute the result (3 - -3b) into the second equation:

3b - 9(3 + 3b) = 6
3b + (-9 x 3) + (-9 x 3b) = 6
3b - 27 - 27b = 6
3b - 27b = 6 + 27
-24b = 33
b = \( \frac{33}{-24} \)
b = -1\(\frac{3}{8}\)


2

The dimensions of this cylinder are height (h) = 4 and radius (r) = 3. What is the volume?

63% Answer Correctly
192π
36π
28π
320π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(32 x 4)
v = 36π


3

What is 4a - 7a?

80% Answer Correctly
-3a
11a2
11
28a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

4a - 7a = -3a


4

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the area is length x width

all interior angles are right angles

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


5

Simplify (5a)(4ab) + (7a2)(6b).

65% Answer Correctly
-22a2b
62a2b
117ab2
-22ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(4ab) + (7a2)(6b)
(5 x 4)(a x a x b) + (7 x 6)(a2 x b)
(20)(a1+1 x b) + (42)(a2b)
20a2b + 42a2b
62a2b