ASVAB Math Knowledge Practice Test 890288 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

Simplify 9a x 5b.

85% Answer Correctly
45ab
45\( \frac{a}{b} \)
14ab
45a2b2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

9a x 5b = (9 x 5) (a x b) = 45ab


2

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

π r2h

4π r2

2(π r2) + 2π rh

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


3

Which of the following statements about a triangle is not true?

57% Answer Correctly

perimeter = sum of side lengths

exterior angle = sum of two adjacent interior angles

sum of interior angles = 180°

area = ½bh


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


4

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

expression

equation

formula

problem


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


5

Find the value of c:
-5c + z = -4
-6c - 3z = 6

42% Answer Correctly
7
1\(\frac{3}{5}\)
-4\(\frac{1}{2}\)
\(\frac{2}{7}\)

Solution

You need to find the value of c so solve the first equation in terms of z:

-5c + z = -4
z = -4 + 5c

then substitute the result (-4 - -5c) into the second equation:

-6c - 3(-4 + 5c) = 6
-6c + (-3 x -4) + (-3 x 5c) = 6
-6c + 12 - 15c = 6
-6c - 15c = 6 - 12
-21c = -6
c = \( \frac{-6}{-21} \)
c = \(\frac{2}{7}\)