ASVAB Math Knowledge Practice Test 891488

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -5c + 3c = -9c - 2y + 3 for c in terms of y.

1\(\frac{1}{6}\)y - 1\(\frac{1}{2}\)
\(\frac{2}{5}\)y - 1\(\frac{3}{5}\)
2\(\frac{3}{7}\)y - \(\frac{1}{7}\)
-1\(\frac{1}{4}\)y + \(\frac{3}{4}\)