When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 5c = 6c - 6x + 8 for c in terms of x.
| \(\frac{1}{4}\)x - 2 | |
| -1\(\frac{1}{3}\)x + 2 | |
| 2\(\frac{1}{3}\)x - \(\frac{1}{3}\) | |
| -1\(\frac{1}{2}\)x + 4 |