The surface area of a cylinder is 2πr² + 2πrh:

sa = 2πr² + 2πrh
sa = 2π(7²) + 2π(7 x 9)
sa = 2π(49) + 2π(63)
sa = (2 x 49)π + (2 x 63)π
sa = 98π + 126π
sa = 224π

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

8z - 5 > \( \frac{z}{-9} \)
-9 x (8z - 5) > z
(-9 x 8z) + (-9 x -5) > z
-72z + 45 > z
-72z + 45 - z > 0
-72z - z > -45
-73z > -45
z > \( \frac{-45}{-73} \)
z > \(\frac{45}{73}\)

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(3 + 5)(4)
a = ½(8)(4)
a = ½(32) = \( \frac{32}{2} \)
a = 16

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s²

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c² = a² + b²
c² = 7² + 7²
c² = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)