| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
Simplify (8a)(2ab) - (3a2)(2b).
| 50ab2 | |
| 22a2b | |
| 10a2b | |
| 50a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(2ab) - (3a2)(2b)
(8 x 2)(a x a x b) - (3 x 2)(a2 x b)
(16)(a1+1 x b) - (6)(a2b)
16a2b - 6a2b
10a2b
Solve for y:
3y + 9 < \( \frac{y}{-2} \)
| y < -2\(\frac{2}{5}\) | |
| y < -1\(\frac{5}{11}\) | |
| y < -2\(\frac{4}{7}\) | |
| y < -1\(\frac{1}{35}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
3y + 9 < \( \frac{y}{-2} \)
-2 x (3y + 9) < y
(-2 x 3y) + (-2 x 9) < y
-6y - 18 < y
-6y - 18 - y < 0
-6y - y < 18
-7y < 18
y < \( \frac{18}{-7} \)
y < -2\(\frac{4}{7}\)
If the base of this triangle is 8 and the height is 8, what is the area?
| 55 | |
| 32 | |
| 54 | |
| 97\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 8 x 8 = \( \frac{64}{2} \) = 32
Which of the following is not required to define the slope-intercept equation for a line?
x-intercept |
|
y-intercept |
|
\({\Delta y \over \Delta x}\) |
|
slope |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
This diagram represents two parallel lines with a transversal. If c° = 15, what is the value of z°?
| 157 | |
| 14 | |
| 152 | |
| 15 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with c° = 15, the value of z° is 15.