ASVAB Math Knowledge Practice Test 896953 Results

Your Results Global Average
Questions 5 5
Correct 0 2.60
Score 0% 52%

Review

1

Solve for c:
c2 + 3c - 40 = 0

57% Answer Correctly
4 or -7
8 or 3
5 or -8
-5 or -9

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 + 3c - 40 = 0
(c - 5)(c + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 5) or (c + 8) must equal zero:

If (c - 5) = 0, c must equal 5
If (c + 8) = 0, c must equal -8

So the solution is that c = 5 or -8


2

On this circle, line segment AB is the:

70% Answer Correctly

circumference

chord

radius

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

Solve 3a + a = 2a - 2z - 3 for a in terms of z.

34% Answer Correctly
-3z - 3
\(\frac{10}{11}\)z - \(\frac{8}{11}\)
-2z - 2
z - 6

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

3a + z = 2a - 2z - 3
3a = 2a - 2z - 3 - z
3a - 2a = -2z - 3 - z
a = -3z - 3


4

Which types of triangles will always have at least two sides of equal length?

53% Answer Correctly

equilateral and isosceles

isosceles and right

equilateral and right

equilateral, isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


5

Solve for c:
-7c - 7 = \( \frac{c}{9} \)

46% Answer Correctly
-\(\frac{20}{23}\)
-\(\frac{63}{64}\)
\(\frac{48}{49}\)
1\(\frac{2}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-7c - 7 = \( \frac{c}{9} \)
9 x (-7c - 7) = c
(9 x -7c) + (9 x -7) = c
-63c - 63 = c
-63c - 63 - c = 0
-63c - c = 63
-64c = 63
c = \( \frac{63}{-64} \)
c = -\(\frac{63}{64}\)