ASVAB Math Knowledge Practice Test 897188 Results

Your Results Global Average
Questions 5 5
Correct 0 3.42
Score 0% 68%

Review

1

Solve for a:
-8a - 6 = 1 + 2a

58% Answer Correctly
-\(\frac{7}{10}\)
\(\frac{5}{8}\)
-\(\frac{1}{9}\)
3

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-8a - 6 = 1 + 2a
-8a = 1 + 2a + 6
-8a - 2a = 1 + 6
-10a = 7
a = \( \frac{7}{-10} \)
a = -\(\frac{7}{10}\)


2

Factor y2 - 10y + 9

53% Answer Correctly
(y + 9)(y + 1)
(y + 9)(y - 1)
(y - 9)(y - 1)
(y - 9)(y + 1)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 9 as well and sum (Inside, Outside) to equal -10. For this problem, those two numbers are -9 and -1. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 10y + 9
y2 + (-9 - 1)y + (-9 x -1)
(y - 9)(y - 1)


3

If BD = 18 and AD = 23, AB = ?

75% Answer Correctly
7
5
13
3

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 23 - 18
AB = 5


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

87% Answer Correctly

pairs

exponents

addition

division


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

Simplify (8a)(5ab) + (2a2)(6b).

65% Answer Correctly
104ab2
52ab2
52a2b
28a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(5ab) + (2a2)(6b)
(8 x 5)(a x a x b) + (2 x 6)(a2 x b)
(40)(a1+1 x b) + (12)(a2b)
40a2b + 12a2b
52a2b