When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 2c = 2c - y + 2 for c in terms of y.
| -2y - \(\frac{1}{2}\) | |
| \(\frac{1}{6}\)y + \(\frac{1}{3}\) | |
| -1\(\frac{2}{5}\)y + \(\frac{3}{5}\) | |
| -\(\frac{1}{2}\)y + 2 |