| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
Breaking apart a quadratic expression into a pair of binomials is called:
normalizing |
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squaring |
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factoring |
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deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
The dimensions of this cube are height (h) = 7, length (l) = 8, and width (w) = 5. What is the volume?
| 40 | |
| 150 | |
| 504 | |
| 280 |
The volume of a cube is height x length x width:
v = h x l x w
v = 7 x 8 x 5
v = 280
Simplify (9a)(4ab) + (7a2)(9b).
| 99a2b | |
| 99ab2 | |
| 208ab2 | |
| 208a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(9a)(4ab) + (7a2)(9b)
(9 x 4)(a x a x b) + (7 x 9)(a2 x b)
(36)(a1+1 x b) + (63)(a2b)
36a2b + 63a2b
99a2b
Which of the following is not required to define the slope-intercept equation for a line?
y-intercept |
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slope |
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\({\Delta y \over \Delta x}\) |
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x-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
If the area of this square is 4, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)