ASVAB Math Knowledge Practice Test 898811

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c + c = -4c - 5x + 3 for c in terms of x.

x - \(\frac{1}{5}\)
1\(\frac{2}{13}\)x - \(\frac{8}{13}\)
5x + 2
-1\(\frac{1}{5}\)x + \(\frac{3}{5}\)