| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
Which of the following statements about a parallelogram is not true?
opposite sides and adjacent angles are equal |
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the area of a parallelogram is base x height |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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a parallelogram is a quadrilateral |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
What is the area of a circle with a diameter of 6?
| 9π | |
| 49π | |
| 16π | |
| 8π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{6}{2} \)
r = 3
a = πr2
a = π(32)
a = 9π
Solve for b:
b2 + 11b + 55 = -4b - 1
| 9 or 3 | |
| -7 or -8 | |
| -2 or -8 | |
| 8 or -5 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 + 11b + 55 = -4b - 1
b2 + 11b + 55 + 1 = -4b
b2 + 11b + 4b + 56 = 0
b2 + 15b + 56 = 0
Next, factor the quadratic equation:
b2 + 15b + 56 = 0
(b + 7)(b + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 7) or (b + 8) must equal zero:
If (b + 7) = 0, b must equal -7
If (b + 8) = 0, b must equal -8
So the solution is that b = -7 or -8
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
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isosceles and right |
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equilateral and isosceles |
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equilateral, isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
If the area of this square is 25, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 8\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)