ASVAB Math Knowledge Practice Test 900075 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

opposite sides and adjacent angles are equal

the area of a parallelogram is base x height

the perimeter of a parallelogram is the sum of the lengths of all sides

a parallelogram is a quadrilateral


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


2

What is the area of a circle with a diameter of 6?

70% Answer Correctly
49π
16π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{6}{2} \)
r = 3
a = πr2
a = π(32)
a = 9π


3

Solve for b:
b2 + 11b + 55 = -4b - 1

49% Answer Correctly
9 or 3
-7 or -8
-2 or -8
8 or -5

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b2 + 11b + 55 = -4b - 1
b2 + 11b + 55 + 1 = -4b
b2 + 11b + 4b + 56 = 0
b2 + 15b + 56 = 0

Next, factor the quadratic equation:

b2 + 15b + 56 = 0
(b + 7)(b + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 7) or (b + 8) must equal zero:

If (b + 7) = 0, b must equal -7
If (b + 8) = 0, b must equal -8

So the solution is that b = -7 or -8


4

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and right

isosceles and right

equilateral and isosceles

equilateral, isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


5

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
4\( \sqrt{2} \)
5\( \sqrt{2} \)
\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)