| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
Which of the following statements about parallel lines with a transversal is not correct?
angles in the same position on different parallel lines are called corresponding angles |
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all of the angles formed by a transversal are called interior angles |
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all acute angles equal each other |
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same-side interior angles are complementary and equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
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normalizing |
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factoring |
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deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
A quadrilateral is a shape with __________ sides.
2 |
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5 |
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4 |
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3 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
The endpoints of this line segment are at (-2, 1) and (2, -9). What is the slope of this line?
| -1\(\frac{1}{2}\) | |
| -2\(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| 1 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -9) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-9.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-10}{4} \)Solve -4b + 2b = 8b + x - 1 for b in terms of x.
| 2x - 4 | |
| \(\frac{1}{12}\)x + \(\frac{1}{12}\) | |
| x + \(\frac{9}{10}\) | |
| -3x + 1\(\frac{2}{3}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-4b + 2x = 8b + x - 1
-4b = 8b + x - 1 - 2x
-4b - 8b = x - 1 - 2x
-12b = -x - 1
b = \( \frac{-x - 1}{-12} \)
b = \( \frac{-x}{-12} \) + \( \frac{-1}{-12} \)
b = \(\frac{1}{12}\)x + \(\frac{1}{12}\)