When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 2c = -5c - 6y + 5 for c in terms of y.
| -3y - 1\(\frac{1}{2}\) | |
| -\(\frac{8}{13}\)y + \(\frac{5}{13}\) | |
| y - \(\frac{5}{6}\) | |
| 5y - 1 |