ASVAB Math Knowledge Practice Test 903681 Results

Your Results Global Average
Questions 5 5
Correct 0 2.78
Score 0% 56%

Review

1

Simplify 8a x 6b.

85% Answer Correctly
48\( \frac{b}{a} \)
48ab
48a2b2
48\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

8a x 6b = (8 x 6) (a x b) = 48ab


2

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c2 + a2

c - a

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


3

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

isosceles and right

equilateral, isosceles and right

equilateral and right

equilateral and isosceles


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


4

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the area of a parallelogram is base x height

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


5

Find the value of a:
-6a + y = 8
9a - y = -3

42% Answer Correctly
-\(\frac{4}{5}\)
\(\frac{33}{35}\)
\(\frac{11}{31}\)
1\(\frac{2}{3}\)

Solution

You need to find the value of a so solve the first equation in terms of y:

-6a + y = 8
y = 8 + 6a

then substitute the result (8 - -6a) into the second equation:

9a - 1(8 + 6a) = -3
9a + (-1 x 8) + (-1 x 6a) = -3
9a - 8 - 6a = -3
9a - 6a = -3 + 8
3a = 5
a = \( \frac{5}{3} \)
a = 1\(\frac{2}{3}\)