When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 2c = c - 3z + 4 for c in terms of z.
| z + \(\frac{1}{2}\) | |
| -1\(\frac{1}{4}\)z + 1 | |
| -8z - 2 | |
| \(\frac{1}{4}\)z - \(\frac{1}{6}\) |