ASVAB Math Knowledge Practice Test 905092 Results

Your Results Global Average
Questions 5 5
Correct 0 3.46
Score 0% 69%

Review

1

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

2

5

3

4


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


2

Solve -2a - 2a = -4a - 3z + 3 for a in terms of z.

34% Answer Correctly
-\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)
-1\(\frac{1}{4}\)z + \(\frac{1}{3}\)
-3\(\frac{1}{2}\)z + \(\frac{1}{2}\)
-\(\frac{7}{9}\)z + \(\frac{1}{3}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-2a - 2z = -4a - 3z + 3
-2a = -4a - 3z + 3 + 2z
-2a + 4a = -3z + 3 + 2z
2a = -z + 3
a = \( \frac{-z + 3}{2} \)
a = \( \frac{-z}{2} \) + \( \frac{3}{2} \)
a = -\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)


3

Which of the following expressions contains exactly two terms?

81% Answer Correctly

binomial

polynomial

monomial

quadratic


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


4

Solve for c:
c2 + 7c - 23 = 4c - 5

48% Answer Correctly
3 or -6
4 or -5
-5 or -6
-3 or -7

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 + 7c - 23 = 4c - 5
c2 + 7c - 23 + 5 = 4c
c2 + 7c - 4c - 18 = 0
c2 + 3c - 18 = 0

Next, factor the quadratic equation:

c2 + 3c - 18 = 0
(c - 3)(c + 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 3) or (c + 6) must equal zero:

If (c - 3) = 0, c must equal 3
If (c + 6) = 0, c must equal -6

So the solution is that c = 3 or -6


5

A right angle measures:

90% Answer Correctly

45°

360°

90°

180°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.