ASVAB Math Knowledge Practice Test 905675 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

The dimensions of this cube are height (h) = 4, length (l) = 4, and width (w) = 4. What is the surface area?

51% Answer Correctly
350
100
96
202

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 4) + (2 x 4 x 4) + (2 x 4 x 4)
sa = (32) + (32) + (32)
sa = 96


2

Find the value of a:
5a + z = 2
-3a - 3z = -1

42% Answer Correctly
-\(\frac{15}{26}\)
-2\(\frac{8}{13}\)
-1\(\frac{10}{29}\)
\(\frac{5}{12}\)

Solution

You need to find the value of a so solve the first equation in terms of z:

5a + z = 2
z = 2 - 5a

then substitute the result (2 - 5a) into the second equation:

-3a - 3(2 - 5a) = -1
-3a + (-3 x 2) + (-3 x -5a) = -1
-3a - 6 + 15a = -1
-3a + 15a = -1 + 6
12a = 5
a = \( \frac{5}{12} \)
a = \(\frac{5}{12}\)


3

If a = 7, b = 5, c = 2, and d = 9, what is the perimeter of this quadrilateral?

88% Answer Correctly
26
12
13
23

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 7 + 5 + 2 + 9
p = 23


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

pairs

addition

exponents

division


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

Factor y2 - 6y - 7

54% Answer Correctly
(y + 7)(y + 1)
(y + 7)(y - 1)
(y - 7)(y + 1)
(y - 7)(y - 1)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -7 as well and sum (Inside, Outside) to equal -6. For this problem, those two numbers are -7 and 1. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 6y - 7
y2 + (-7 + 1)y + (-7 x 1)
(y - 7)(y + 1)