When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 4c = -9c + 6z - 3 for c in terms of z.
| \(\frac{7}{16}\)z - \(\frac{5}{16}\) | |
| \(\frac{2}{5}\)z - \(\frac{3}{5}\) | |
| z - 1 | |
| \(\frac{5}{7}\)z + \(\frac{2}{7}\) |