| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.23 |
| Score | 0% | 65% |
Solve -8a - 7a = 2a - 8x + 3 for a in terms of x.
| \(\frac{1}{6}\)x - 1\(\frac{1}{3}\) | |
| \(\frac{1}{10}\)x - \(\frac{3}{10}\) | |
| 12x + 3 | |
| \(\frac{1}{2}\)x - 1\(\frac{3}{4}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-8a - 7x = 2a - 8x + 3
-8a = 2a - 8x + 3 + 7x
-8a - 2a = -8x + 3 + 7x
-10a = -x + 3
a = \( \frac{-x + 3}{-10} \)
a = \( \frac{-x}{-10} \) + \( \frac{3}{-10} \)
a = \(\frac{1}{10}\)x - \(\frac{3}{10}\)
If a = c = 6, b = d = 7, what is the area of this rectangle?
| 42 | |
| 6 | |
| 21 | |
| 12 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 6 x 7
a = 42
If BD = 13 and AD = 23, AB = ?
| 6 | |
| 2 | |
| 10 | |
| 12 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDThe dimensions of this cube are height (h) = 6, length (l) = 1, and width (w) = 7. What is the surface area?
| 110 | |
| 112 | |
| 38 | |
| 180 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 1 x 7) + (2 x 7 x 6) + (2 x 1 x 6)
sa = (14) + (84) + (12)
sa = 110
If side x = 10cm, side y = 5cm, and side z = 6cm what is the perimeter of this triangle?
| 21cm | |
| 25cm | |
| 19cm | |
| 32cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 10cm + 5cm + 6cm = 21cm