ASVAB Math Knowledge Practice Test 90802

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9a - 6a = -4a - 9z + 3 for a in terms of z.

\(\frac{5}{12}\)z + \(\frac{1}{2}\)
\(\frac{3}{5}\)z - \(\frac{3}{5}\)
-2\(\frac{1}{2}\)z + \(\frac{1}{2}\)
\(\frac{9}{13}\)z - \(\frac{1}{13}\)