When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3a + 5a = 8a - 6z + 1 for a in terms of z.
| z + 1\(\frac{2}{5}\) | |
| -\(\frac{7}{15}\)z + \(\frac{2}{15}\) | |
| 2\(\frac{1}{5}\)z - \(\frac{1}{5}\) | |
| -4z + 5 |