ASVAB Math Knowledge Practice Test 908981 Results

Your Results Global Average
Questions 5 5
Correct 0 2.89
Score 0% 58%

Review

1

Simplify (2a)(6ab) + (4a2)(3b).

65% Answer Correctly
24ab2
56a2b
b2
24a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(6ab) + (4a2)(3b)
(2 x 6)(a x a x b) + (4 x 3)(a2 x b)
(12)(a1+1 x b) + (12)(a2b)
12a2b + 12a2b
24a2b


2

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

a parallelogram is a quadrilateral

opposite sides and adjacent angles are equal

the area of a parallelogram is base x height

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π r

c = π r2

c = π d2

c = π d


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


4

The dimensions of this cube are height (h) = 9, length (l) = 6, and width (w) = 3. What is the volume?

83% Answer Correctly
135
84
162
216

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 9 x 6 x 3
v = 162


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
\( \sqrt{2} \)
2\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)