ASVAB Math Knowledge Practice Test 909048

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a + 3a = 4a + 5z - 2 for a in terms of z.

2\(\frac{1}{2}\)z - \(\frac{3}{4}\)
-6z - 4
-1\(\frac{1}{2}\)z - 3\(\frac{1}{2}\)
-z + 1