ASVAB Math Knowledge Practice Test 909933 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

The endpoints of this line segment are at (-2, 6) and (2, 0). What is the slope of this line?

46% Answer Correctly
1
-1\(\frac{1}{2}\)
2\(\frac{1}{2}\)
2

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, 0) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)
m = -1\(\frac{1}{2}\)


2

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

obtuse, acute

vertical, supplementary

supplementary, vertical

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


3

If AD = 26 and BD = 18, AB = ?

75% Answer Correctly
14
19
18
8

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 26 - 18
AB = 8


4

If angle a = 31° and angle b = 56° what is the length of angle d?

56% Answer Correctly
151°
145°
153°
149°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 31° - 56° = 93°

So, d° = 56° + 93° = 149°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 31° = 149°


5

A right angle measures:

90% Answer Correctly

180°

90°

360°

45°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.