| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
Simplify (5a)(2ab) + (9a2)(6b).
| 44a2b | |
| 64a2b | |
| 64ab2 | |
| 105a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(2ab) + (9a2)(6b)
(5 x 2)(a x a x b) + (9 x 6)(a2 x b)
(10)(a1+1 x b) + (54)(a2b)
10a2b + 54a2b
64a2b
The dimensions of this cube are height (h) = 6, length (l) = 5, and width (w) = 4. What is the volume?
| 315 | |
| 168 | |
| 32 | |
| 120 |
The volume of a cube is height x length x width:
v = h x l x w
v = 6 x 5 x 4
v = 120
The dimensions of this cylinder are height (h) = 9 and radius (r) = 3. What is the surface area?
| 28π | |
| 110π | |
| 168π | |
| 72π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 9)
sa = 2π(9) + 2π(27)
sa = (2 x 9)π + (2 x 27)π
sa = 18π + 54π
sa = 72π
If BD = 22 and AD = 24, AB = ?
| 2 | |
| 8 | |
| 6 | |
| 5 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDThe dimensions of this trapezoid are a = 4, b = 2, c = 5, d = 5, and h = 2. What is the area?
| 18 | |
| 20 | |
| 7 | |
| 28 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(2 + 5)(2)
a = ½(7)(2)
a = ½(14) = \( \frac{14}{2} \)
a = 7