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For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
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c2 + a2 |
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c2 - a2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
The endpoints of this line segment are at (-2, 8) and (2, 0). What is the slope of this line?
| 2\(\frac{1}{2}\) | |
| 2 | |
| 3 | |
| -2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 8) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (8.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)If angle a = 52° and angle b = 58° what is the length of angle d?
| 128° | |
| 145° | |
| 116° | |
| 148° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 52° - 58° = 70°
So, d° = 58° + 70° = 128°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 52° = 128°
Which of the following statements about a triangle is not true?
perimeter = sum of side lengths |
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sum of interior angles = 180° |
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exterior angle = sum of two adjacent interior angles |
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area = ½bh |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Simplify (2a)(5ab) + (5a2)(3b).
| 25a2b | |
| 5ab2 | |
| 5a2b | |
| -5ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(5ab) + (5a2)(3b)
(2 x 5)(a x a x b) + (5 x 3)(a2 x b)
(10)(a1+1 x b) + (15)(a2b)
10a2b + 15a2b
25a2b