When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 6c = -8c + 8z + 8 for c in terms of z.
| \(\frac{1}{2}\)z + 2 | |
| -\(\frac{1}{2}\)z - 1\(\frac{3}{4}\) | |
| -6\(\frac{1}{2}\)z + 1 | |
| \(\frac{5}{8}\)z + \(\frac{7}{8}\) |