ASVAB Math Knowledge Practice Test 914035 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

quadrilateral

rhombus

trapezoid

triangle


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


2

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

formula

expression

equation

problem


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


3

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

division

addition

pairs

exponents


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


4

Solve 8a + 4a = 3a + 3y + 3 for a in terms of y.

34% Answer Correctly
1\(\frac{3}{4}\)y + \(\frac{1}{2}\)
\(\frac{1}{3}\)y - \(\frac{2}{3}\)
-\(\frac{2}{3}\)y - 2
-\(\frac{1}{5}\)y + \(\frac{3}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

8a + 4y = 3a + 3y + 3
8a = 3a + 3y + 3 - 4y
8a - 3a = 3y + 3 - 4y
5a = -y + 3
a = \( \frac{-y + 3}{5} \)
a = \( \frac{-y}{5} \) + \( \frac{3}{5} \)
a = -\(\frac{1}{5}\)y + \(\frac{3}{5}\)


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)