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|---|---|---|
| Questions | 5 | 5 |
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Find the value of b:
-6b + x = -8
-6b - 3x = -2
| 2\(\frac{1}{5}\) | |
| 1\(\frac{5}{11}\) | |
| \(\frac{5}{29}\) | |
| 1\(\frac{1}{12}\) |
You need to find the value of b so solve the first equation in terms of x:
-6b + x = -8
x = -8 + 6b
then substitute the result (-8 - -6b) into the second equation:
-6b - 3(-8 + 6b) = -2
-6b + (-3 x -8) + (-3 x 6b) = -2
-6b + 24 - 18b = -2
-6b - 18b = -2 - 24
-24b = -26
b = \( \frac{-26}{-24} \)
b = 1\(\frac{1}{12}\)
If BD = 11 and AD = 14, AB = ?
| 3 | |
| 6 | |
| 8 | |
| 13 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDSolve for x:
-9x + 3 < -2 - 2x
| x < -\(\frac{4}{7}\) | |
| x < 4 | |
| x < 1\(\frac{2}{3}\) | |
| x < \(\frac{5}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-9x + 3 < -2 - 2x
-9x < -2 - 2x - 3
-9x + 2x < -2 - 3
-7x < -5
x < \( \frac{-5}{-7} \)
x < \(\frac{5}{7}\)
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
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midpoints |
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trisects |
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intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Order the following types of angle from least number of degrees to most number of degrees.
acute, right, obtuse |
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right, obtuse, acute |
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acute, obtuse, right |
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right, acute, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.