ASVAB Math Knowledge Practice Test 917126

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a - 5a = -2a - 2z + 4 for a in terms of z.

\(\frac{2}{3}\)z + \(\frac{2}{9}\)
\(\frac{3}{8}\)z + \(\frac{1}{2}\)
1\(\frac{2}{7}\)z + \(\frac{2}{7}\)
\(\frac{1}{13}\)z + \(\frac{1}{13}\)