ASVAB Math Knowledge Practice Test 920485

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -c - 2c = -3c - 7z - 6 for c in terms of z.

-2\(\frac{1}{2}\)z - 3
-1\(\frac{3}{8}\)z + \(\frac{3}{8}\)
\(\frac{1}{14}\)z - \(\frac{1}{14}\)
-\(\frac{1}{10}\)z + \(\frac{1}{10}\)