ASVAB Math Knowledge Practice Test 921548

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c - 3c = 9c + 2z + 4 for c in terms of z.

\(\frac{1}{5}\)z - \(\frac{3}{5}\)
-5z + 4
-3z + 3\(\frac{1}{2}\)
-\(\frac{5}{6}\)z - \(\frac{2}{3}\)