ASVAB Math Knowledge Practice Test 922347 Results

Your Results Global Average
Questions 5 5
Correct 0 3.39
Score 0% 68%

Review

1

What is 8a6 - 3a6?

74% Answer Correctly
a612
24a6
5a12
5a6

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a6 - 3a6 = 5a6


2

Which of the following expressions contains exactly two terms?

84% Answer Correctly

binomial

monomial

quadratic

polynomial


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


3

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

84% Answer Correctly

First

Last

Odd

Inside


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


4

Which of the following statements about a triangle is not true?

58% Answer Correctly

sum of interior angles = 180°

exterior angle = sum of two adjacent interior angles

area = ½bh

perimeter = sum of side lengths


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


5

Solve 7c - 6c = 2c + 5z + 7 for c in terms of z.

35% Answer Correctly
\(\frac{6}{7}\)z + \(\frac{2}{7}\)
1\(\frac{1}{8}\)z - \(\frac{7}{8}\)
2\(\frac{1}{5}\)z + 1\(\frac{2}{5}\)
17z - 3

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

7c - 6z = 2c + 5z + 7
7c = 2c + 5z + 7 + 6z
7c - 2c = 5z + 7 + 6z
5c = 11z + 7
c = \( \frac{11z + 7}{5} \)
c = \( \frac{11z}{5} \) + \( \frac{7}{5} \)
c = 2\(\frac{1}{5}\)z + 1\(\frac{2}{5}\)